TURBOMOLE Modules > Ricc2
frequency mismatch in cc density module
xiang:
Hi there,
I'm calculating an ADC(2) level excitation energies. So after the preoptimization converged and called cc density module to calculate overlap between left/right vectors (guess in cc_1den), there is an error by printing two unequal frequencies and following:
=================
internal module stack:
--------------------------
ricc2
cc_exci
cc_1den
ccintleftvec
=================
frequency mismatch
ricc2 ended abnormally
Would someone lend a hand?
Best,
Xiang
Arnim:
Hello,
could you share what was printed before that?
Cheers,
Arnim
xiang:
thanks for replying, sure, please check the following:
+=======================================================================+
| type: RE0 symmetry: a state: 3 |
+-----------------------+-----------------------+-----------------------+
| occ. orb. index spin | vir. orb. index spin | coeff/|amp| % |
+=======================+=======================+=======================+
| 43 a 43 | 46 a 46 | 0.70140 49.2 |
| 43 a 43 | 47 a 47 | -0.66027 43.6 |
| 45 a 45 | 46 a 46 | 0.14644 2.1 |
| 43 a 43 | 58 a 58 | -0.08214 0.7 |
+=======================+=======================+=======================+
norm of printed elements: 0.95611
Info: copy ADC(2) right eigenvectors into left eigenvector files.
======== CC DENSITY MODULE ========
current wave-function model: ADC(2)
calculating overlap between 3 left and right vector(s)
density nr. cpu/min wall/min L R
------------------------------------------------------
1 0.20 0.01 LE0 RE0
-6.240487094410323E-002 -6.240332690596439E-002
========================
internal module stack:
------------------------
ricc2
cc_exci
cc_1den
ccintleftvec
========================
frequency mismatch
ricc2 ended abnormally
Arnim:
I am not sure what went wrong there. You could try to simply restart the job.
If that doesn't help, change the number of excitation (nexc or npre). That can sometimes lead to a better numerical behavior.
Best
Arnim
xiang:
Dear Arnim,
many thanks, I will try with a new input.
Best,
Xiang
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